Question

a number consists of two digits whose sum is 9 . if the 9 is subtracted from the number the digits the inter change there places. find the number​

Answer 1

Answer:

Step-by-step explanation:

Let us assume, x and y are the two digits of the two-digit number

Therefore, the two-digit number = 10x + y  and reversed number = 10y + x

Given:

x + y = 9 -------------1

also given:

10x + y - 27 = 10y + x

9x - 9y = 27

x - y = 3 --------------2

Adding equation 1 and equation 2

2x = 12

x = 6

Therefore, y = 9 - x = 9 - 6 = 3

The two-digit number = 10x + y = 10*6 + 3 = 63

Answer 2

Step-by-step explanation:

Let the digits at ones place be x

Then the digits at tens place=9-x (sum of two digits is 9)

Therefore the no.=10 (9-x)+x=90-10x+x=90-9x

Now,no. obtained by reversing the digits=10x+9-x=9x+9

it is given if 9 is subtracted from the no.,it's digits are interchanged.

no.-9=no. obtained by reversing the digits.

90-9x-9=9x+9

81-9x=9x+9

81-9=9x+9x

18x=72

x=72/18

x=4

digits at

ones place=x=4

tens place=9-x=9-4=5

the no. is 54....

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