Question

زوار
A number consists of two digits whose sum is eight. if eight is added to the number its digits are reversed find the number.
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Answer 1

Let the number be 10x+y

then its digits are x and y

according to question

10x+y+8=10y+x

9x-9y=-8

x+y=8 (given)

after solving both equations

9x-9y=-8

9x+9y=72

18x=64

x=32/9

y=40/9

number=10x+y

320/9+40/9

=40