A number consists of two digits whose sumn is 9. 1 27 is subtracted from the numbers
digits are reversed. Find the number.
A number is divided into two parts such that one part is 10 more than the other. If the two
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Answers
Correct question :
A number consists of two digits whose sumn is 9. when 27 is subtracted from the number digits are reversed. Find the number.
Answer:
Original number = 63
Explanation:
given that,
A number consists of two digits whose sumn is 9
let the ones digit of the number be x
and ten's digit be y
so,
the number = 10y + x
now,
given the sum of its digits = 9
so,
x + y = 9. ...(1)
now,
also,
given that,
when 27 is subtracted from the number digits are reversed.
here,
reversed digit number = 10x + y
according to the question,
10y + x - 27 = 10x + y
10y - y + x - 10x = 27
9y - 9x = 27
9(y - x) = 27
y - x = 27/9
y - x = 3 ...(2)
now,
we have,
y + x = 9. ....(1)
y - x = 3. ...(2)
adding the both equations
y + x + y - x = 9 + 3
2y = 12
y = 12/2
y = 6
now,
from eqn (1)
y + x = 9
putting the value of y
6 + x = 9
x = 9 - 6
x = 3
y = 6
so,
number = 10y + x
= 10(6) + 3
= 60 + 3
= 63
so,
Original number = 63
Correct question
A number consists of two digits whose sumn is 9. 27 is subtracted from the numbers digits are reversed. Find the number.
Answer:
Original number = 63
Step by step explanations :
Refer to the attachment
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