Math, asked by mahtoranjan87, 1 month ago

A number exceeds 12% of itself by 440, find the number?​

Answers

Answered by namratasaha80
0

Answer: 500

Step-by-step explanation:

Let the number be x.

Therefore, 12% of X = 12/100 × x = 3x/25

Given that the number exceeds 12% of itself by 440.

x-3x/25=440

22x/25=440

x= 440×25/22

x=40×25/2

x=20×25/1

x= 20×25

x= 500

Hence, the correct answer is 500.

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