A number exceeds 20% of itself by 40. Find the number.
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Answer:
50
Step-by-step explanation:
let the number be n.
we have that:
n=20% of n+40
or:
n=20/100n+40;
n-20/100n=40;
100n-20n/100=40;
80n/100=40;
4n/5=40;
4n=40×5;
4n=200;
n=200:4=50
Hence the number is 50.
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