Question

A number exceeds the other by 26. If their
sum is 54, find the numbers.​

Answer 1

Answer:

The Numbers are 40 and 14.

Step-by-step explanation:

Given :

One number exceeds other by 26

Their sum = 54

To find :

The numbers

Solution :

Let the numbers be -

• One as y
• Second as y + 26

$\bigstar \: \boxed{\sf{y + (y + 26) = 54}}$

$\sf{\implies} \: y + (y + 26) = 54 \\ \\ \sf{\implies} \: 2y + 26 = 54 \\ \\ \sf{\implies} \: 2y = 54 - 26 \\ \\ \sf{\implies} \: 2y = 28 \\ \\ \sf{\implies} \: y = \dfrac{28}{2} \\ \\ \sf{\implies} \: y = 14$

One number = 14

$\rule{300}{1.5}$

★ $\textsf{\underline{\underline{Value of (y + 26) }}}$

$\sf{\implies} \: y +26 \\ \\ \sf{\implies} \: 14 + 26 \\ \\\sf{\implies} \: 40$

Second Number = 40

$\therefore$ The Numbers are 40 and 14.