Question

a number has two digits. The units digit is 4 less than the tens digit. the sum of the digits devided by the difference of the digits is 2. find the number.

Answer 1

let the tens digit be x
let the ones digit be x-4
so,
the sum of the digits divided by the difference of the digits is 2
x+(x-4) ÷ x-(x-4) =2
2x-4 ÷ 4 =2
cross multiply 4 from denominator of LHS to RHS
you get
2x-4 = 8
bring -4 from LHS to RHS
you get
2x = 8+4
2x = 12
bring 2 to RHS
you get
x = 6
so the two digit number is
62. ( since tens digit is x and ones digit is x-4 you get 6 6-4 so 62)






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