a number has two digits whose sum is 10 if 54 is added to the number, it's digits get interchange . find the number
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qhlet the no be xy
A/Q
x+y=10-----(1)
xy+54=yx
=>10x +y +54=10y+x
=>10x+y-10y-x=-54
=>9x-9y= -54
=>x-y= -54/9
=>x-y=-6-------(2)
Now, (1)+(2)=>x+y+x-y=10-6
=>2x=4
=>x=2
(1)=>2+y=10
=>y=8
therefore the reqd. two digit no is 28
A/Q
x+y=10-----(1)
xy+54=yx
=>10x +y +54=10y+x
=>10x+y-10y-x=-54
=>9x-9y= -54
=>x-y= -54/9
=>x-y=-6-------(2)
Now, (1)+(2)=>x+y+x-y=10-6
=>2x=4
=>x=2
(1)=>2+y=10
=>y=8
therefore the reqd. two digit no is 28
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