Question

A number increased by 84 equals 160 times its reciprocal . Find the nimber.

Answer 1

given:

$x + 84 = 160 \times ( \frac{1}{x + 84} )$
now,

$= > (x + 84) (x + 84)= 160 - 84 \\ \\ = > {(x + 84)}^{2} = 76 \\ \\ = > {(x + 84)} = 2 \sqrt{19} \\ \\ = > x = 2 \sqrt{19} - 84$