A number is 27 more than the number obtained by reversing its digits. If its unit's and ten's digit are x and y?
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Let the number digit of unit is x and ten number digit is y
Then number=x+10y
If we reversing number digit by ten number digit the number =y+10x
Given that the number is 27 more then reversed number
So(x+10y)−(y+10x)=27
Or x+10y−y−10x=27
Or 9y−9x−27=0
Or y−x−3=0
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