Question

A number is 56 greater than the average of its one-third, quarter and one-twelfth.
Find the number...

please solve this...​

Answer 1

Answer:

SUPPOSE NUMBER IS X

3RD NUMBER = X/3

QUARTER = X/4

12TH NUMBER = X/12

THE NUMBER IS 56 GREATER THAN THE AVERAGE OF 3RD,4TH, AND 12TH

SET UP THE EQUATION

TOTAL OF X/3 +X/4 + X/12 = 8X/12

AVERAGE = 1/3 × 8X/12 = 8X=36

8X/36 = X— 56

8X = 36X — 36 × 56

8X — 36X = — 36× 56

28X = 36 × 56

X = 72

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