A number is chosen from the set S = 1, 2, . . . , 1000. What is the probability that the chosen number is multiple of 2 and 3?
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Answer:
0.166
Step-by-step explanation:
Answer :
We have integers 1, 2, 3,… 1000
∴ Total number of outcomes, n(S) = 1000
The multiple of 2 and 3 both are 6,12,… 996.
Let m be the number of terms in above series.
∴ mth term = 996
We know that,
am = a + (m – 1)d
Here, a = 6 and d = 6
Putting the value, we get
6 + (m – 1)6 = 996
⇒ 6 + 6m –6 = 996
⇒ m = 166
= n(E)
P(E) = n(E) / n(S)
P(E) = 166 / 1000 = 0.166
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