a number is decreased by a factor of 6 and when it's increased by 28 the difference is 49 .the smallest such number is
Answers
Answer:
4663
Step-by-step explanation:
The given numbers are 520 and 468.
The smallest number which when increased by 17 is exactly divisible by both 520 and 468 is obtained by subtracting 17 from the LCM of 520 and 468.
520=2×2×2×5×13
468=2×2×3×3×13
LCM of 520 and 468 = 2×2×2×3×3×5×13=4680
Smallest number which when increased by 17 is exactly divisible by both 520 and 468=4680−17
=4663
Answer:
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