Question

how many square tiles of side 30cm will be required for the floor 18m long and 15m wide if a cost of a tile is 2.50 find the cost of covering the floor with the tiles​

Answer 1

Answer:

rupess 750.00

Step-by-step explanation:

first convert 18m to cm =1800cm and 15m=1500cm so 1500×1800/30×30 = 300

We need 300 tiles the cost of each covering tile=rupees2.50

300×2.50 = rupess 750.00

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Answer 2

Answer:

The square tiles of side 30cm will be required for the floor 18m long and 15m wide if a cost of a tile is 2.50 the cost of covering the floor with the tiles​ is 7500rs

Step-by-step explanation:

The length of the floor $l=18m=1800cm$

the breadth of the floor $b=15m=1500cm$

since the floor is a rectangle the total area of the floor is $A=l*b$

⇒ $A=1800*1500=2700000cm^{2}$

the side of the square tile $a=30cm$

since the tile is a square the area of one tile $A=a^{2}$

⇒$A=30*30=900cm^{2}$

now the number of tiles is given as the area of the floor divided by the area of one tile

⇒  $\frac{2700000}{900}=3000$

the cost of one tile is $2.5rs/-$

now the total cost of the tile is the product of the total number of tiles and the price of one tile

⇒$3000*2.5=7500rs/-$