Question

A number is divided into two equal such one part is 10 more than the other. if the two parts are in the ratio 5:3 find the number and the two parts?
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Answer 1

Given :-

• A number is divided into two parts such as one part is 10 more than the other.
• The two parts are in ratio 5:3

To Find :-

Number and the two parts

Solution :-

Let the smaller part be x

$\tt \implies \: \dfrac{x}{x + 10} = 5 \ratio \: 3$

$\tt \implies \: \dfrac{x}{x + 10} = \dfrac{5}{3}$

By Cross Multiplication

$\tt \implies \: 3(x + 10) = 5(x)$

$\tt \implies \: 3 \times x + 3 \times 10 = 5 \times x$

$\tt \implies \: 3x + 30 = 5x$

$\tt \implies \: 5x - 3x =30$

$\tt \implies \: 2x = 30$

$\tt \implies \: x = \dfrac{30}{2}$

$\tt \implies \: x = 15$

Now,

Let's find the both parts

$\tt \implies \: {1}^{st} part = x = 15$

$\tt \implies \: {2}^{nd} \: part = x + 10 = 15 + 10 = 25$

$\tt \implies \: number \: = 40$

Answer 2

YOUR ANSWER÷

Since the two parts are in the ratio 5:3, then let the first number be 5x and second number be 3x. As second number is 10 more than the other, so it will be 3x+10.

5x=3x+10

2x=10

x=5

The first number becomes 5(5)=25 and second number becomes 3(5)=15.

The new number will be 25+15=40.

HOPE IT HELPS U LOT MARK AS BRAINLIEST. .

PLS THANKS.