Math, asked by dishank73, 11 months ago

A number is divided into two parts in such a way that 80%

of 1st part is 3 more than 60% of 2nd part and 80% of 2nd part is 6

more than 90% of the 1st part. Then the number is​

Answers

Answered by hancyamit2003
2

Answer:

The answer is 135

Step-by-step explanation

Let the 2 parts of the no. be x and y.

By question,

80%of x=60% of y +3..................(1)

And,. 80% of y= 90%of x +6.............(2)

From (1),

(80/100)*x=(60y/100)+3

Or,4x/5=(3y/5)+3

Or,4x/5=(3y+15)/5

Or,4x=3y+15

Or,4x-3y-15=0........................(3)

From (2) , we have

80y/100=(90x/100)+6

Or,4y/5=(9x/10)+6

Or,4y/5=(9x+60)/10

Or,8y=9x+60

Or,9x-8y+60=0......................(4)

Multiplying equation (3) throughout by 8 we get

32x-24y-120=0........(A)

Multiplying equation (4) throughout by 3 we get

27x-24y+180=0.........(B)

Subtracting B from A we get

5x-300=0

Or, 5x=300

Therefore x=60

Now putting this value of x in any of the equation above ( here let us put in equation 3 for simplicity) we get

4×60-3y-15=0

Or,240-15=3y

Or,225/3=y

Therefore, y=75

Hence the required number is (x+y)=(60+75)=135

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