Question

A number is divided into two parts such one part is 10 more than the other if there is two parts are in the ratio of 5:3 find the number and two parts​

Answer 1

5/3=x+10/x

3x+30=5/3x

3x-5/3x=30

4/3x=30

x=30*3/4

x=90/4

x=45/2

let 1st no

45/2*5

105

2nd no

45/2*3

37.5

Answers

Answer 2

$\huge{\green{\underline{\underline{\textsf{\green{Answer}}}}}}$

$\sf{Let \:one\: part \:of \:the \:number \:be\: x}$

$\sf{then,\: the\: other \:part\: be \:x+10}$

$\sf{According \:to\: the\: condition,\: in\: the\: question,}$ $\sf{we\: get}$

$\sf{⇒ \dfrac{x+10}{x}}$

$\sf{⇒3x+30=5x}$

$\sf{⇒2x=30}$

$\sf{⇒x=15}$

$\sf{Therefore, }$

$\sf{x+10= 15+10 = 25}$

$\sf{then, \:the\: new \:number = 15+25=40}$

$\sf{Hence, \: the \: two \: parts \: of \: a \: numbers \: are \: 15}$ $\sf{and \: 25 \: and \: the \: number \: is \: 40}$