Question

Given tan A = 0.75 , find sin A , cos A , cot A ( angle A is an acute angle in Triangle ABC right angled at B )

Answer 1

Answer:

we can get your answer by this

Answer 2

Answer:

sin A = 3/5  

cos A = 4/5

cot A = 4/3

Step-by-step explanation:

Given, tan A = 0.75

Writing it into fraction form we have, tan A = $\frac{3}{4}$

We know, tan A = $\frac{perpendicular}{base}$

                           = $\frac{3}{4}$ ---- (1)

thus, perpendicular = 3

                       base = 4

According to the Pythagoras theorem, in a right-angled triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the other two sides.

Mathematically,  $hypotenuse^{2} = perpendicular^2+base^2$

                            $hypotenuse^{2}= 3^2+4^2\\ hypotenuse^2 = 9+16\\ hypotenuse^2 = 25\\ hypotenuse= 5$

Now,

     $sin A = \frac{perpendicular}{hypotenuse}\\ sin A = \frac{3}{5}$  

       $cos A = \frac{base}{hypotenuse}\\ cos A = \frac{4}{5}$

        $cot A = \frac{1}{tan A} \\cot A = \frac{1}{3/4} \\\\cot A = \frac{4}{3}$

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Trignometric identies:https://brainly.in/question/11812006

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