Math, asked by narendermodi74461, 9 months ago

A number is divided into two parts such that one part is 10 mare than other. if the the two parts are in the ratio 5:3, find the number and the two parts.

Answers

Answered by stpstrix
0

Answer:

Let the two parts be x and y

Given,

x=y+10----1 x÷y=5÷3-----2

Substitute eq 1 in the second equation...

(y+10)×3=5×y

on solving we get

y=15 and x=25

Answered by Anonymous
1

Answer:

A number is divided in to two parts such that one part is 10 more than the other. If the two parts are in the ratio 5:3, find the number and the two parts.

solution:

       let one part of number = x

           therefore ,  other part of number = x+10

   according to question ,

             x+10/x=5/3

           3(x+10)= 5x

           3x+30 =5x

             30 = 5x -3x

             30 = 2x

     or x=30/2

         x=15

therefore one part of number = 15

and other part = 15+10 =25

hence number = 15+25 =40

Step-by-step explanation:

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