Math, asked by 970296, 8 months ago

A number is divided into two parts, such that one part is 10 more than the other. If the two parts are in the ratio 5 : 3, find the number and the two parts.​

Answers

Answered by srikanthn711
1

Let one part of the number be x

Then the other part of the number = x + 10

The ratio of the two numbers is 5 : 3

Therefore, (x + 10)/x = 5/3

⇒ 3(x + 10) = 5x

⇒ 3x + 30 = 5x

⇒ 30 = 5x - 3x

⇒ 30 = 2x

⇒ x = 30/2

⇒ x = 15

Therefore, x + 10 = 15 + 10 = 25

Therefore, the number = 25 + 15 = 40

The two parts are 15 and 25.

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Answered by Anonymous
0

Answer :

A number is divided in to two parts such that one part is 10 more than the other. If the two parts are in the ratio 5:3, find the number and the two parts.

solution:

      let one part of number = x

          therefore ,  other part of number = x+10

  according to question ,

            x+10/x=5/3

          3(x+10)= 5x

          3x+30 =5x

            30 = 5x -3x

            30 = 2x

    or x=30/2

        x=15

therefore one part of number = 15

and other part = 15+10 =25

hence number = 15+25 =40

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