Question

a number is divided into two parts such that one part is 10 more than the other if the two parts are in the ratio of 5:3 find the numbers and the two parts​

Answer 1

Ratio of Two Parts=5:3

Let First Part=5x

Let Second Part=3x

First Part is 10 more Than Second Part.

MEANS

3x+10=5x

5x-3x=10

2x=10

$x = \frac{\cancel{10}}{\cancel2}$

x=5

First Part=5x=5×5=25

Second Part=3x=3×5=15

Number=25+15=40

CHeck

First Part is 10 more than Second Part.

=15+10=25

Hence It is Right.

$\boxed{\mathbf{\large{First\:Part=25}}}$

$\boxed{\mathbf{\large{Second\:Part=15}}}$

$\boxed{\mathbf{\large{Number=40}}}$

Answer 2

Answer:

Step-by-step explanation:

Let the first part be x and

 second part be x+10

Now,

x+10/x= 5/3

= 3 (x+10) = 5x

= 3x+30=5x

= 3x- 5x= -30

= -2x = -30

= x = -30/-2  

= x = 15