Question

a number is divided into two parts such that one part is 12 more than the other . if the two parts in the ratio 1:2. find the numbers?

Answer 1

QUESTION:

A number is divided into two parts such that one part is 12 more than the other . if the two parts in the ratio 1:2. find the numbers?

ANSWER

Original number = 36

parts of number = 12 and 24

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Step-by-step explanation:

given that,

a number is divided into two parts

let the number be x

such that one part is 12 more than the other

so,

let the one part of x be y

so,

if one part = y

then,

another number = y + 12

ACCORDING TO THE QUESTION

x = y + y + 12

x = 2y + 12

x - 2y = 12. ....(2)

also given that,

the two parts in the ratio 1:2.

so,

parts are y and y + 12

y/(y + 12) = 1/2

2y = y + 12

2y - y = 12

y = 12

now,

putting the value of y on (1)

x - 2y = 12

x - 2(12) = 12

x - 24 = 12

x = 12 + 24

x = 36

y =12

parts of the number = y = 12

and, y + 12

= 12 + 12

= 24

so,

Original number = 36

parts of number = 12 and 24

Answer 2

Answer:

12,24

Step-by-step explanation:

Let one part be x.

Given that other part is 12 more than first.

So, the other part becomes x+12 .

Ratio of the parts =1:2

So,

We can write x:x+12 =1:2

$\implies\frac{x}{x + 12} = \frac{1}{2}$

$\implies2x = x + 12$

$\implies \: 2x - x = 12$

$\boxed{ \boxed{ \implies \: x = 12}}$

So, the first part is 12 .

Other part =x+12

=12+12

=24

The original number is 12+24

=36 .