Question

i +i²+i³+............i to the power 2019
value of this
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Answer 1

I hope it would help you

Answer 2

Answer:

use sum of nth term of a GP

here a=I

r=I

so sum of 2019 term

is i(l-i^2019)/(1-i)

and i^4n=1

so i(1+i)/(1-i)

(i-1)(1-i)=-1 answer