Question

A number is divisible by 11 and 91. What is the sum of the digits of the smallest such number ?

Answer 1

LCM of 91 and 11 = 1001

Sum of the digits is 1+0+0+1 = 2

Answer 2

Answer:

The “sum of the digits of the smallest number” that can be divisible by ‘11 and 91’ is 2.

Solution:

The smallest number which is divisible by “11 and 91” = L.C.M of 11 and 91

The ‘Least Common Multiple’ of the 11 and 91, gives out the least number that can be divisible by 11 and 91.

Hence, both the numbers are prime numbers, so both of them cannot be divided by any other number other than their own.

$=11\times91=1001$

The resultant number becomes 1001.

Thus the sum of digits of the smallest number i.e.,

1001 = 1 + 0 + 0 + 1 = 2  

Hence, the “sum of the digits of the smallest number” that can be divisible by ‘11 and 91’ is 2.