Question

A number is divisible by both 4 and 7. By what other number will it be
always divisible. Give reason.
16
Using
od write the prime factoriz:​

Answer 1

Answer:

if a number is divisible by both 4&7,then it will always divisible by it's least common multiple of 4,7

here LCM of 4,7 is 28.

28 and all the multiples of 28 also divisible by both 4&7.

Answer 2

Answer:

The other number that $x$ is divisible by, is 28.

Explanation:

Given a number is divisible by both 4 and 7.

Let the number be $x$.

If the number $x$ is divisible by both 4 and 7, then it will always be divisible by the least common multiple(LCM) of 4 and 7.

So, need to find the least common multiple of 4 and 7

The prime factorization of 4 is $2 \times2$ or $2^2$.

The prime factorization of 7 is $7$ or $7^1$.

Thus, the LCM of 4 and 7 is $2\times2\times7=28$.

So, the other number that $x$ is divisible by, is 28.

And also all the multiples of 28 are divisible by both 4 and 7.

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