Question

A number is increased by 10% and then decreased by 10% . The actual decrease in ________

please give answer fast ​

Answer 1

Answer:

Actual decrease in percentage is 1%

Step-by-step explanation:

let the number increase by 10% be

$x + \frac{10x}{100} = x + \frac{1}{10}= \frac{11x}{10}$

then the number decreases by 10%,

$\frac{11x}{10} - \frac{11x}{10} \times \frac{10}{100} \\ = \frac{11x}{10} - \frac{11x}{100} = \frac{99x}{100}$

decrease in percentage is,

$x - \frac{99x}{100} = \frac{1x}{100}$

$as \: decrease \: \% = \frac{net \: decrease \: in \: \%}{original \: number} \times 100\% \\ \\ = > decrease \: \% = \frac{x}{100} \div x \times 100\% \\ = > decrease\% = \frac{1}{100} \times 100\% = 1\%$

therefore, actual decrease in percentage is 1%

please, mark this as brainlest