Question

a number is increased by 10% and then increased by 10% what it is net increase or decrease percent ​

Answer 1

Let, the number be,'x'

10% of x =10x/100

New number =x+10x/100

                     =(100x+10x)/100

                   = 110x/100

                   =11x/10

10% of 11x/10 =(11x*10/10*100)

                    =11x/100

∴ The new number =(x+11x/100)

                               = (100x+11x)/100

                              = 111x/100

So, the increased amount =(111x/100)-x

                                           =(111x-100x)/100

                                          = 11x/100

So, the increased % ={(11x/100)/x}*100

                                 = (11x*100/x*100)

                                 =11%