A number is increased by 10% and then it is decreased by 10%. Find the net change percent in the number
Answers
Solution :-
Let the required number be 100.
Then, according to the question.
⇒ Firstly, the number is increased by 10 %
⇒ 100 + (100*10)/100
⇒ 100 + 10
= 110
Secondly, it is decreased by 10 %
⇒ 110 - (110*10)/100
⇒ 110 - 11
⇒ 99
Net increase or decrease percentage
= (Original Number - New Number)*100/100
⇒ (100 - 99)*100/100
⇒ (1*100)/100
⇒ 100/100
= 1 %
So, net decrease is 1 %.
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ANSWER
→ Let the number be x
∴ Increased by 10%
∴ New number =(10+100)% of x
=(
10
11x
)
Now decreased by 10%
∴ New number =(100−10)% of
10
11x
=90% of
10
11x
=
10
9
×
10
11x
=(
100
99x
)
∴ Net numbers (x) decreased
∴ % decrease =
⎝
⎜
⎜
⎛
x
x−
100
99x
⎠
⎟
⎟
⎞
×100
∴ % decrease =(
100
1
×100)×100
∴