Question

A number is increased by 20% and then again by 20%. By what percent should the incrased number be reduced so as to get back the original number?

Answer 1

Let the number be 100.

Increasing 100 by 20% = (100+20)∗(100/100)=120.(100+20)∗(100/100)=120.

Now, Increasing 120 by 20% =(100+20)∗(120/100)=144(100+20)∗(120/100)=144

Now we need to find the percentage of 144 which can take us back to 100(the original number), i.e. 44.
So out Statement should be x% of 144 is 44.

Writing it Mathematically:

(x/100)∗(144)=44(x/100)∗(144)=44

x=(100∗44)/144x=(100∗44)/144

x=30.5