Question

What is the rms voltage in series rl circiuit if the voltage across is 256 and 192 respectively

Answer 1

RMS voltage in series RL is circuit is nothing but resultant of the of both resistor voltage and inductor voltage

ie.,



that implies V = root of( sq(256)+ sq(192))

V= 320v

Answer 2

Concept:

In the case of the RL circuit, the RMS voltage is given by the equation-

V = √V₁² + V₂²

Given:

The voltage across the RL circuit is 256 and 192 respectively

Find:

We need to determine the RMS voltage in series.

Solution:

A circuit type with a mix of inductors and resistors is known as an RL Circuit (resistor-inductor circuit), sometimes known as an RL Network or an RL Filter, and it is often powered by a power source.

As a result, an RL circuit has an inductor and a resistor coupled to one another in either parallel or series.

In the case of the RL circuit, the RMS voltage is given by the equation-

V = √V₁² + V₂²

We have, V₁  as 256 V and V₂ as 192 V

Therefore, the equation for RMS voltage becomes-

V = √V₁² + V₂² = √(256)² + (192)²

V = √65,536 + 36,864

V = √102,400

V = 320V

Thus, the RMS voltage in a series RL circuit is 320V.

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