Question

a number is increased by 20% and then decreased by 20%. what is the net percent of increase or decrease​

Answer 1

Answer:

4%

Explanation:

Let us suppose the number to be x.

As per the first case, the number is increased by 20%

Hence: x+ ((x*20)/100)

Resultant number is ‘6x/5’

As per the second case, resultant number is then decreased by 20%

Hence : (6x/5) - (((6x/5) * 20)/100)

Which is (6x/5) - (6x/25) = 24x/25.

The original number being x, we witness a net decrease in the overall process as (24x/25) is less than x.

Therefore Net decrease_

x - (24x/25)= x/25

Net decrease in percentage= (Net Decrease/ Initial Value) * 100%

Thus, ((x/25)/x) * 100% = 4%

So, the answer is 4%.......

prefer to it child!!

Answer 2

Answer:

4% Decrease

Explanation:

Consider the number is 100

On increasing by 20 %

We get 120

Again by decreasing it by 20 % (of 120)

We get 120-24 = 96

So net it is decreased by 4%