Math, asked by kumarpankaj58197, 4 months ago

A number is increased by 20% and, then it is decreased
by 10%, the net change in the number​

Answers

Answered by apple4u
0

Answer:

let number be x

after increasing by 20% it becomes=1.2x

after decreasing by 10% it becomes =0.9×1.2x=1.08x

so the ultimately number increased by 8%

Answered by yashkain70
0

Answer:

8%

Step-by-step explanation:

Let the original number = 100

Increased by 20%

∴ New number = 100 + 20 = 120

Decreased by 10% = (120 × 10)/100 = 12

∴ New number = 120 – 12 = 108

Overall change = 108 – 100 = 8

Reqd. percentage = 8/100 × 100 = 8% (increased)

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