A number is increased by 20% and, then it is decreased
by 10%, the net change in the number
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Answered by
0
Answer:
let number be x
after increasing by 20% it becomes=1.2x
after decreasing by 10% it becomes =0.9×1.2x=1.08x
so the ultimately number increased by 8%
Answered by
0
Answer:
8%
Step-by-step explanation:
Let the original number = 100
Increased by 20%
∴ New number = 100 + 20 = 120
Decreased by 10% = (120 × 10)/100 = 12
∴ New number = 120 – 12 = 108
Overall change = 108 – 100 = 8
Reqd. percentage = 8/100 × 100 = 8% (increased)
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