Question

A number is less than 443 and greater than 397. The sum of the ones digit and the tens digit in the number is 5. The ones digit is 3. What is the number.
(1) 423
(2) 432
(3) 323
(4) 322

Answer 1

Answer is option @
____________________
By problem


Digit at one's place = 3

Sum of tens and ones digit is 5

So, tens digit = 5-3 =2

So,

The required term will be in form (x23)

From the given option either it can be 1 or 3

But since the required term lies between 443 and 397 and 323< 397..

So, the required term is 423.
__________________________
Hope this is ur required answer

Proud to help you