Question

A number is selected at random from first 20 natural numbers . Find the probability of the

number being:

(a) a prime number (b) a multiple of 6 (c) an even number

(d) numbers which are divisible both by 4 and 6



*Please answer this with the correct answer, ignore if you don't know the answer, absurd answer's will be moderated*

Answer 1

Step-by-step explanation:

a) prime numbers between 1 to 20 = 8

= 8/20

B) multiple of 6 between 1 to 20 = 3

= 3/20

c) even number between 1 to 20= 10

= 10/20

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Answer 2

$\large\frak \purple{Question :}$

A number is selected at random from first 20 natural numbers . Find the probability of thenumber being:

(a) a prime number

(b) a multiple of 6

(c) an even number

(d) numbers which are divisible both by 4 and 6

$\large\frak \green{Formula :}$

$\sf {Probability = \frac{favorable \: outcomes}{total \: number \: of \: outcomes} }$

$\large \frak \orange{Solution :}$

$\sf(a) \frac{8}{20}$

$\sf (b) \frac{3}{20} \\ \\ \sf (c) \frac{10}{20} \\ \\ \sf (d) \frac{1}{20}$

$\sf \color{azure}\fcolorbox{pink}{black}{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: @Saanvigrover2007 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:}$