A number is selected at random from first thirty natural numbers. What is the chance that it is a multiple of either 3 or 13?
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EXPLANATION:-
First thirty natural numbers are=1 to 30
no.of multiples of 3 in between these numbers=10( 3×10)
no.of multiples of 13 in between two numbers=2(13×2)
PROBABILITY =favourable outcomes/total outcomes
favourable outcomes=10+2=12
total outcomes=30
probability is=12/30 or 2/5
hope this helps you!!
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