Question

A number is selected at random from the set of number {11,12,....99}.What is the probability that selected number contains the digit 9?

Answer 1

Answer:

Step-by-step explanation:

Total no. Which have last digit as 9= 10

Let the given event we assume as a

.°. P(A)= no. with last digit as 9/total no.

.°. P(A)= 10/89

Answer 2

Given,

The set of numbers = {11,12,---, 99}

To find,

The probability that the selected number contains the digit 9.

Solution,

The probability that the selected number containing the digit 9 will be 18/89.

We can easily solve this problem by following the given steps.

We know that the probability of an event is found using the following formula:

P(E) = Number of favourable outcomes/total number of outcomes

According to the question,

The set of numbers = {11,12,---, 99}

So, the total number of outcomes will be (99-11)+1.

Total number of outcomes = 89

Now, the numbers containing the digit 9 = 19,29,39,49,59,69,79,89,90,91,92,93,94,95,96,97,98 and 99 (total = 18)

P(E) = 18/89

Hence, the probability that the selected number contains the digit 9 is 18/89.