Question

A number is selected from first 50 natural numbers. What is the probability that it is a multiple of 3 or 5?
(a)$\frac{13}{25}$
(b)$\frac{21}{50}$
(c)$\frac{12}{25}$
(d)$\frac{23}{50}$

Answer 1

SOLUTION :

The correct option is (d) : 23/50.

Given : A number is selected from first 50 natural numbers .

First 50 natural numbers  = {1, 2, 3 …. 50}

Total number of possible outcome = 50

Let E = Event of getting a number which is a multiple of 3 and 5  

Multiples of 3 and 5 are = 3,5,6, 9, 10, 12, 15, 18,20, 21, 24, 25, 27,30, 33 ,35, 36 ,39, 40 ,42, 45 48, 50

No. of favorable outcomes = 23

Probability ,P(E) = Number of favourable outcomes / total number of outcomes

P(E) = 23/50 = 2/50  

Hence, the Probability of getting a number which is a multiple of 3 and 5 is 23/50.

HOPE THIS ANSWER WILL HELP  YOU…

Answer 2

Answer:

$\frac{23}{30}$

Step-by-step explanation:

Find total Possible Outcomes  

First 50 natural numbers are

⇒ 1, 2, 3, 4, 5.....................50

So , total possible outcome = 50

Find Multiples of 3 and 5

⇒ $3,5,6, 9, 10, 12, 15, 18,20, 21, 24, 25, 27,30, 33 ,35, 36 ,39, 40 ,42, 45 48, 50$

So , number of favourable outcomes = 23

Find the Probability

Probability = $\frac{Favouable \ Outcome }{Total \ Outcome}$

⇒ P(E) = $\frac{Favouable \ Outcome }{Total \ Outcome}$

⇒ $P(E) = \frac{23}{50}$

Therefore , Probability of selecting 50 natural numbers which is multiple of 3 and 5 is  \frac{23}{50}[/tex]

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