A number lock has 3 rings each is marked 0 to 9 in how many ways the lock can't be opened
Answers
Each ring is marked 0 to 9:
⇒ There are 10 possible choices
There are 3 rings:
⇒ Total number of possible choices = 10 x 10 x 10 = 1000
Assuming the lock that open be opened with one combination:
⇒ Total number of ways that the lock can't be open = 1000 - 1 = 999
Answer: There are 999 ways that the lock can't be opened.
Given:
3 Rings
0 - 9 Numbered
To find:
The number of ways the padlock cannot be opened.
Solution:
As there are 10 numbers from 0 to 9,
There are 10 possibilities.
10 numbers in all three Rings,
So,
Total number of possibilities = 10^3
Total number of possibilities = 1000
As there is one unlock code for the lock,
The total number of ways that the lock can't be opened = Total number of possibilities - one unlock code
1000 - 1
The total number of ways that the lock can't be opened = 999 ways.
Hence, there are 999 ways the lock cannot be opened.