a number lock has a 3 digit key. hint of these three digit key given, can you Crack the code 6 8 2 one number is correct and well placed, 6 1 4 one number is correct but wrong placed,2 0 6 two numbers are correct but wrong placed, 7 3 8 nothing is correct,7 8 0 one number is correct but wrong placed, then what is correct lock code? ,
Answers
Statement A: 6 8 2 - one number is correct and well placed
Statement B: 6 1 4 - one number is correct but wrongly placed.
Statement c: 2 0 6 - two numbers are correct but wrongly placed.
Statement D: 7 3 8 - All are wrong.
Statement : E: 7 8 0 - one number is correct and wrong placed.
Conclusion: by the statements A, B , C and D we can say that number 2 is correct with its place in unit place.
Another number is 4 with its place in tens place.
By statement D and E we can say 0 is the correct number which should be placed in hundreds place.
Hence correct code is
0 4 2
Therefore, the co-de of the given numerical lock is 042.
Decoding the clues given:
On observing the rules given, from the fourth rule, we get that the lock contains no numbers from the list [7, 3, 8]. So, from the first rule 6, 2 remains.
From the second rule, we get that one number among 6, 1, 4 is correct but wrongly placed. But the number 6 is in the same position in rules 1 and 2. So, there is no chance of 6 being among the three numbers of the lock.
So, from the first rule, we get that the number at the last position is 2 as it says that the number is well placed.
_ _ 2
In the third rule, if we eliminate 6, the remaining numbers are 2, 0. They are correct but wrongly placed. As 2 is fixed with the last position, 0 goes for the first position as per the rule.
0 _ 2
Now, from rule 2, we get that one number is correct among 1, 4 but is wrongly placed. If 1 is correct, it would be well placed and that contradicts the rule which says that the number is wrongly placed. So, the correct number that should be in the second position is 4
0 4 2
Therefore, the co-de of the given numerical lock is 042.
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