Question

A number m is such that when divided by 30,36,and45 the remainder is always 7 find the smallest possible value of m

Answer 1

Answer:

Step-by-step explanation:

First we have to find the LCM of 30,36 and 45

30=3*5*2

45=3*5*3

36=3*3*2*2

LCM =180

therefore m=180+7=187                since 7 is the remainder in all cases

Hope that helps. Please choose my answer as the brainliest!