Math, asked by monitaagrawal, 1 month ago

A number multiply by itself added
to y​

Answers

Answered by agrock11590
0

Step-by-step explanation:

To get the answer we have to solve the following equation:

x + x = x*x

then 2x = x²

then x = x²/2

then 0 = x²/2 - x

which is a model of the quadratic polynomial y = ax² + bx + c

where a = 1/2, b = -1 and c = 0

we compute the discriminant delta (D)

recall: D = b² - 4ac

then D = (-1)² - 4*(1/2)*0 = 1 – 0 = 1

D is positive (=1) then 2 solutions (x and x’)

recall: x = -b + SQRT(D) and x' = -b - SQRT(D)

then x = -(-1) + SQRT(1) = 1 + 1 = 2

then x' = -(-1) - SQRT(1) = -1 - 1 = 0

conclusion:

• what is (are) the number(s) when multiplied or added to itself (themselves), give(s) the same result?

• answer: 0 and 2

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