Question

a number N in such that when it is divided by 27,30,45, the remeinder is always 3 .find the smallest value of n

Answer 1

The smallest value of n is 273

Step-by-step explanation:

• To find the least number that will be divisible by 27,30 and 45 so that it always leave a remainder 3 ;we have to find the L.C.M(Least Common Multiple).
• The L.C.M of 27,30,45 is 270.
• But, according to question we need a number that leaves a remainder 3 when  divided by 27,30 and 45.
• So, if we add 3 to the Lowest Common Multiple of 27,30 and 45 we get 273.
• Therefore,the smallest value of n which is divided by 27,30 and 45 so that it always leaves a remainder 3 is 273.

Answer 2

Answer:

Step-by-step explanation: