Question

a number of 2 digits has 3 for its ones digit and the sum of digits is 1/7 of the number itself.what is the number​

Answer 1

Answer:

63....As, unit digit = 3 , Suppose ten digit =X, then a/c to situation... (10x+3)1/7 =x+3...solving this equation we get X= 6...hence two digit number is 63.

Answer 2

Answer: The correct answer is 63.

Step-by-step explanation:

Generalized form is that when a number is written as sum of products of its digits with their respective place value.

An usual form is the form in which numbers are written normally.

Taking an example : 123  is usual form

100 x 1 + 10 x 2  + 3 is said to be its generalized form

Now abc = 100a + 10b + c

So ab = 10a + b

Here ab and abc represent numbers

First find sum of digits.
⇒a+3

Using generalized form of number to find value,

⇒10a+3

Using the given fact that sum of digits is $\frac{1}{7}$ of number itself and solve for a.

⇒ a+3 = 1/7 ( 10a +3)

⇒7(a + 3) = 10a + 3
⇒7a+21 = 10a + 3

⇒10a-7a = 21 - 3
⇒3a = 18
⇒a = 6

The required number is 10a+3 = 10x 6+ 3 = 60+3= 63

Hence, the number is 63.

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