Question

a number of two digits exceeds four times the sum of its digits by 3 and it is increased by 18 on reversing the digits.find the number.​

Answer 1

Answer:

35

Step-by-step explanation:

Let the number be 10y+x

Reversed number=10x+y

According to question

10y+x=4(x+y)+3

10y+x=4x+4y+3

6y-3x=3

2y-x=1.....(1)

10y+x+18=10x+y

9y-9x=-18

y-x=-2......(2)

From (1),x=2y-1

Put x in (2)

y-(2y-1)=-2

y-2y+1=-2

-y=-3

y=3

x=2(3)-1=5

x=5

Number=35

Answer 2

Sorry for wrong answer. Report and remove. Because I can't delete