Question

A number on being divided by 10 and 11 successively leaves the remainders 5 and 7 respectively. Find the number. best will be marked as brainliest

Answer 1

Answer: a number divided by 10 leaves the remainder 5 the number will be 15

A number divided by 11 leaves the remainder 7 is 40

Step-by-step explanation:

Answer 2

Answer:

The least number that satisfies the given condition is 95.

Step-by-step explanation:

Let the number be x.

Given:-

When x is divided by 10 the remainder is 5, &

When x is divided by 11 the remainder is 7.

We know, Number/Dividend = Divisor * Quotient + Remainder.

Here we do not have a quotient. So let the quotient be m & n for 10 & 11 as divisor.

Therefore,

10 * m + 5 = x.   & 11 * n + 7 = x

Comparing both we have,  10m + 5 = 11n + 7

or 10m = 2 + 11n.

So we will have multiple values of m & n. Here whenever n has a number ending with 8, it will satisfy the equation.

So the values of n will be 8, 18, 28, 28,...  & m will be 9, 20, 31, 42,...

The natural number which satisfies the given condition will be 95, 205, 315, ...

The least number is 95.