Question

Calculate the heat developed in 30 minutes when 3A current flows through an electric iron box designed to work under 230V.​

Answer 1

Explanation:

H=i2RT we know

so R=V/I

H=VIT (T=time)

=230×3×30×60

=1242000 Joule sec

Answer 2

Answer:

the heat developed in iron box is 1242 kj

Explanation:

In general, while electric powered cutting-edge passes thru a conductor, it produces warmth. This is known as the heating impact of electrical cutting-edge.

used to iron apparel. This warmth is shipped to the sole (base) plate of the electrical iron thru conduction that's pressed in opposition to the apparel to make it wrinkle free. Thermostat product of Bimetallic stirp interior allows it manipulate the temperature of the bottom plate.

V=230 v

I=3 A

t=30 m=30 x 60 =1800 sec

H=V it = 230 x 3 x 1800 =1242000 J = 1242 kJ

#SPJ3