Question

a number plus two thirds of itseld plus one half of itself . plus one seventh of itself equals 97 . find the number

Answer 1

a number plus two third of itself
1x = x
:
plus one half of itself
+ x
:
plus one seventh of itself
+ x
:
equal 97. 
x + x + x = 97 
:
find the no.
:
A multiple of all 3 denominators is 42:
42*x + 42*x + 42*x = 42(97)

CAncel out the denominators:
14(5x) + 21x + 6x = 4074
:
70x + 21x + 6x = 4074
:
97x = 4074 
:
x = 4074/97
:
x = 42
:
:
Check solution in original equation:
*42 + *42 + *42 = 97
70 + 21 + 6 = 97
:

Answer 2

Hope it will help you