Question

a number plus two thirds of itself plus one half of itself plus one seventh of itself equals 97 find the number

Answer 1

let the number be x
x+(2/3)x+(1/2)x+(1/7)x=97

lcm of (1,3,2,7)=42

=>(42x/42)+(28x/42)+(21x/42)+(6x+42)=97
=>(42x+28x+21x+6x)/42=97
=>97x/42=97
=>97x=97×42
=>x=(97/97)×42
=>x=1×42
=>x=42

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Answer 2

Answer:

Let the number be x4

x+(2/3)x+(1/2)x+(1/7)x=97

lcm of (1,3,2,7)=42

=>(42x/42)+(28x/42)+(21x/42)+(6x+42)=97

=>(42x+28x+21x+6x)/42=97

=>97x/42=97

=>97x=97×42

=>x=(97/97)×42

=>x=1×42

=>x=42