A number say z is exactly, the four times the sum of its digits and twice the product of the digits find the number
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Let the no. z be 10x + y
10x + y = 4 (x + y)
10x + y = 4x + 4y
6x-3y = 0
2x-y = 0 eq1
10x + y = 2xy eq2
From eqi y = 2x put y in eq2
10x + 2x = 2xy
12x = 2xy
y = 12x/ 2x = 6
Put value of y in eq1
2x-6 = 0
x = 6/2 = 3
No. was 10x + y
= 10x3 +6
= 36
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