if x = 2+√5, find the value of (x+1/x)²
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Answer:
Given that ,
x = 2 + √5
x^2 + 1 / x ^ 2 = ?
Solution
1/x = 1 / 2 + √ 5 .
BY rationalization ,
= 1 × ( 2 - √ 5 ( ) + 2 + √ 5 ) × ( 2 - √ 5)
= 2 - √ 5 / (2 ) ^ 2 - ( √ 5 ) ^ 2
= 2 - √ 5 / 4 - 5
= 2 - √ 5 ) 4 - 1
= - 2 + √ 5
x^ 2 + 1 / x ^ 2
= ( 2 + √ 5 ) ^ 2 + ( -2 + √ 5 ) ^ 2
= (2)^ 2 + ( √ 5 ) ^ 2 + 2 × 2 + √ 5 + ( - 2 ) ^ 2 + ( √ 5 ) ^ 2 + 2 × ( - 2 )
= 4 + 5 + 4 √ 5 + 4 + 5 - 4 √ 5
= 9 + 4 √ 5 79 - 4 √ 5
= 18 .
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